What is the integral from pi/6 to pi of sin(θ) ?

The integral from pi/6 to pi of sin(θ) is 1+(sqrt(3))/2

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integral from pi/6 to pi of sin(θ)

\int_{\frac{π}{6}}^{π} sin (θ) d θ

1 + \frac{3}{2}

Decimal

1.86602 \dots

Solution steps

\int_{\frac{π}{6}}^{π} sin (θ) d θ

Use the common integral:

\int sin (θ) d θ = - cos (θ)

= [- cos (θ)]_{\frac{π}{6}}^{π}

Compute the boundaries:

1 + \frac{3}{2}

= 1 + \frac{3}{2}

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\int_{0}^{2} \frac{2}{1 - x ^{2}} d x

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What is the integral from pi/6 to pi of sin(θ) ?
The integral from pi/6 to pi of sin(θ) is 1+(sqrt(3))/2