What is the integral from 4 to 16 of 1/(sqrt(x)) ?

The integral from 4 to 16 of 1/(sqrt(x)) is 4

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integral from 4 to 16 of 1/(sqrt(x))

\int_{4}^{16} \frac{1}{x} d x

4

Solution steps

\int_{4}^{16} \frac{1}{x} d x

Apply the Power Rule

: [2 x^{\frac{1}{2}}]_{4}^{16}

= [2 x^{\frac{1}{2}}]_{4}^{16}

Apply radical rule:

a^{\frac{1}{n}} = n a

= [2 x]_{4}^{16}

Compute the boundaries:

4

= 4

\int_{- 1}^{1} sin (x) d x

\int_{1}^{4} \frac{e ^{\frac{1}{x}}}{x ^{2}} d x

\int_{1}^{2} \frac{cos ( x )}{x} d x

\int_{1}^{3} \frac{e ^{\frac{1}{x}}}{x ^{2}} d x

\int_{2}^{5} x^{2} + 5 x d x

What is the integral from 4 to 16 of 1/(sqrt(x)) ?
The integral from 4 to 16 of 1/(sqrt(x)) is 4