What is the integral from 0 to pi/6 of cos(x) ?

The integral from 0 to pi/6 of cos(x) is 1/2

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integral from 0 to pi/6 of cos(x)

\int_{0}^{\frac{π}{6}} cos (x) d x

\frac{1}{2}

Decimal

0.5

Solution steps

\int_{0}^{\frac{π}{6}} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= [sin (x)]_{0}^{\frac{π}{6}}

Compute the boundaries:

\frac{1}{2}

= \frac{1}{2}

\int_{0}^{\frac{π}{2}} sin^{2} (θ) d θ

\int_{4}^{9} ln (1 + x) d x

\int_{- 1}^{1} x^{5} d x

\int_{- 1}^{7} \frac{1}{x + 1} d x

\int_{1}^{8} 0.2 x^{2} + 1 d x

What is the integral from 0 to pi/6 of cos(x) ?
The integral from 0 to pi/6 of cos(x) is 1/2