What is the integral from 0 to 1 of 2x^3 ?

The integral from 0 to 1 of 2x^3 is 1/2

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integral from 0 to 1 of 2x^3

\int_{0}^{1} 2 x^{3} d x

\frac{1}{2}

Decimal

0.5

Solution steps

\int_{0}^{1} 2 x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{1} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{1}

= 2 [\frac{x ^{4}}{4}]_{0}^{1}

Compute the boundaries:

\frac{1}{4}

= 2 \cdot \frac{1}{4}

Simplify

= \frac{1}{2}

\int_{2}^{4} x^{2} - 2 x - 3 d x

\int_{- π}^{π} x cos (x) d x

\int_{0}^{\frac{π}{2}} x d x

\int_{- 1}^{2} 2 x d x

\int_{1}^{x} (2 x^{2} y^{- 2} + 2 y) d y

What is the integral from 0 to 1 of 2x^3 ?
The integral from 0 to 1 of 2x^3 is 1/2