What is the integral from pi/2 to 0 of cos(θ) ?

The integral from pi/2 to 0 of cos(θ) is -1

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integral from pi/2 to 0 of cos(θ)

\int_{\frac{π}{2}}^{0} cos (θ) d θ

- 1

Solution steps

\int_{\frac{π}{2}}^{0} cos (θ) d θ

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{\frac{π}{2}} cos (θ) d θ

Use the common integral:

\int cos (θ) d θ = sin (θ)

= - [sin (θ)]_{0}^{\frac{π}{2}}

Compute the boundaries:

1

= - 1

\int_{0}^{1} \frac{1}{( 1 + x ) ^{2}} d x

\int_{2}^{7} ln (1 + x) d x

\int_{0}^{s i n (x)} 1 - t^{2} d t

\int_{2}^{4} 2 x d x

\int_{0}^{2} x ln (8 x) d x

What is the integral from pi/2 to 0 of cos(θ) ?
The integral from pi/2 to 0 of cos(θ) is -1