What is the integral from-5 to 5 of (x^5)/(x^2+4) ?

The integral from-5 to 5 of (x^5)/(x^2+4) is 0

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integral from-5 to 5 of (x^5)/(x^2+4)

\int_{- 5}^{5} \frac{x ^{5}}{x ^{2} + 4} d x

0

Solution steps

\int_{- 5}^{5} \frac{x ^{5}}{x ^{2} + 4} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

\frac{x ^{5}}{x ^{2} + 4} :

Odd

= 0

\int_{0}^{1} 2 y d y

\int_{- π}^{0} sin (n x) d x

\int_{0}^{3} x e^{- x^{2}} d x

\int_{9}^{16} \frac{5}{x ^{3}} d x

\int_{\frac{π}{3}}^{π} sin (θ) d θ

What is the integral from-5 to 5 of (x^5)/(x^2+4) ?
The integral from-5 to 5 of (x^5)/(x^2+4) is 0