What is the integral from 0 to 2pi of sqrt(1-cos(x)) ?

The integral from 0 to 2pi of sqrt(1-cos(x)) is 4sqrt(2)

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integral from 0 to 2pi of sqrt(1-cos(x))

\int_{0}^{2 π} 1 - cos (x) d x

42

Decimal

5.65685 \dots

Solution steps

\int_{0}^{2 π} 1 - cos (x) d x

Rewrite using trig identities

= \int_{0}^{2 π} 2 sin^{2} (\frac{x}{2}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{2 π} sin^{2} (\frac{x}{2}) d x

Apply exponent rule:

a^{2} = ∣ a ∣

= 2 \cdot \int_{0}^{2 π} sin (\frac{x}{2}) d x

Eliminate Absolutes

= 2 \cdot \int_{0}^{2 π} sin (\frac{x}{2}) d x

Apply u-substitution

: \int_{0}^{π} sin (u) \cdot 2 d u

= 2 \cdot \int_{0}^{π} sin (u) \cdot 2 d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot 2 \cdot \int_{0}^{π} sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= 2 \cdot 2 [- cos (u)]_{0}^{π}

Compute the boundaries:

2

= 2 \cdot 2 \cdot 2

Simplify

= 42

\int_{1}^{3} 4 x - x^{2} d x

\int_{0}^{x} \frac{sin ( x )}{x} d x

\int_{1}^{2} \frac{1}{t + e} d t

\int_{e^{y}}^{y} \frac{y ln ( x )}{x} d x

\int_{\frac{π}{3}}^{\frac{π}{2}} sin (x) d x

What is the integral from 0 to 2pi of sqrt(1-cos(x)) ?
The integral from 0 to 2pi of sqrt(1-cos(x)) is 4sqrt(2)