What is the integral from-1 to 8 of sqrt(1+x) ?

The integral from-1 to 8 of sqrt(1+x) is 18

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integral from-1 to 8 of sqrt(1+x)

\int_{- 1}^{8} 1 + x d x

18

Solution steps

\int_{- 1}^{8} 1 + x d x

Apply u-substitution

: \int_{0}^{9} u d u

= \int_{0}^{9} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{9}

= [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{9}

Compute the boundaries:

18

= 18

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What is the integral from-1 to 8 of sqrt(1+x) ?
The integral from-1 to 8 of sqrt(1+x) is 18