What is the integral from-2 to 2 of xln(1+x^4) ?

The integral from-2 to 2 of xln(1+x^4) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-2 to 2 of xln(1+x^4)

\int_{- 2}^{2} x ln (1 + x^{4}) d x

0

Solution steps

\int_{- 2}^{2} x ln (1 + x^{4}) d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

x ln (1 + x^{4}) :

Odd

= 0

\int_{0}^{2 π} sin (t) cos (t) d t

\int_{0}^{\frac{π}{2}} \frac{1}{sin ( x )} d x

\int_{s i n (x)}^{c o s (x)} t^{2} d t

\int_{0}^{x} \frac{x}{2} d x

\int_{1}^{4} x (5 x - 3) d x

What is the integral from-2 to 2 of xln(1+x^4) ?
The integral from-2 to 2 of xln(1+x^4) is 0