What is the integral from 0 to 0.3 of sin(x^2) ?

The integral from 0 to 0.3 of sin(x^2) is 1.25331…\S(sqrt(2/pi)*0.3)-1.25331…\S(sqrt(2/pi)*0)

Popular >

integral from 0 to 0.3 of sin(x^2)

\int_{0}^{0.3} sin (x^{2}) d x

1.25331 \dots § (\frac{2}{π} \cdot 0.3) - 1.25331 \dots § (\frac{2}{π} \cdot 0)

Solution steps

\int_{0}^{0.3} sin (x^{2}) d x

Use the nonelementary integral:

\int sin (x^{2}) d x = \frac{π}{2} § (\frac{2}{π} x)

= [\frac{π}{2} § (\frac{2}{π} x)]_{0}^{0.3}

Simplify

= [1.25331 \dots § (\frac{2}{π} x)]_{0}^{0.3}

Compute the boundaries:

1.25331 \dots § (\frac{2}{π} \cdot 0.3) - 1.25331 \dots § (\frac{2}{π} \cdot 0)

= 1.25331 \dots § (\frac{2}{π} \cdot 0.3) - 1.25331 \dots § (\frac{2}{π} \cdot 0)

\int_{0}^{2} (x^{2} - x) d x

\int_{0}^{1} \frac{1}{x x} d x

\int_{0}^{x} ln (z + 2) d z

\int_{0}^{x} t d t

\int_{0}^{l n (3)} 5 e^{x} d x

What is the integral from 0 to 0.3 of sin(x^2) ?
The integral from 0 to 0.3 of sin(x^2) is 1.25331…\S(sqrt(2/pi)*0.3)-1.25331…\S(sqrt(2/pi)*0)