What is the integral from-1 to 1 of t^2 ?

The integral from-1 to 1 of t^2 is 2/3

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integral from-1 to 1 of t^2

\int_{- 1}^{1} t^{2} d t

\frac{2}{3}

Decimal

0.66666 \dots

Solution steps

\int_{- 1}^{1} t^{2} d t

Apply the Power Rule

: [\frac{t ^{3}}{3}]_{- 1}^{1}

= [\frac{t ^{3}}{3}]_{- 1}^{1}

Compute the boundaries:

\frac{2}{3}

= \frac{2}{3}

\int_{0}^{t} cos (x) d x

\int_{0}^{π} cos^{2} (\frac{x}{2}) d x

\int_{0}^{1} a x + b x^{2} d x

\int_{- 1}^{1} - 1 - x^{2} d x

\int_{0}^{4} x^{2} e^{x^{3}} d x

What is the integral from-1 to 1 of t^2 ?
The integral from-1 to 1 of t^2 is 2/3