What is the integral from-pi/4 to pi/4 of sec^2(x) ?

The integral from-pi/4 to pi/4 of sec^2(x) is 2

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integral from-pi/4 to pi/4 of sec^2(x)

\int_{- \frac{π}{4}}^{\frac{π}{4}} sec^{2} (x) d x

2

Solution steps

\int_{- \frac{π}{4}}^{\frac{π}{4}} sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= [tan (x)]_{- \frac{π}{4}}^{\frac{π}{4}}

Compute the boundaries:

2

= 2

\int_{1}^{x^{2}} \frac{sin ( t )}{t} d t

\int_{1}^{4} 3 d x

\int_{1}^{2} (x^{2} + \frac{1}{x ^{2}}) d x

\int_{y}^{3 y} cos (2 x + y) d x

\int_{0}^{1} x (1 - x^{4})^{\frac{3}{2}} d x

What is the integral from-pi/4 to pi/4 of sec^2(x) ?
The integral from-pi/4 to pi/4 of sec^2(x) is 2