What is the integral from t to 3t of (sin(x))/x ?

The integral from t to 3t of (sin(x))/x is \Si(3t)-\Si(t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from t to 3t of (sin(x))/x

\int_{t}^{3 t} \frac{sin ( x )}{x} d x

Si (3 t) - Si (t)

Solution steps

\int_{t}^{3 t} \frac{sin ( x )}{x} d x

Use the nonelementary integral:

\int \frac{sin ( x )}{x} d x = Si (x)

= [Si (x)]_{t}^{3 t}

Compute the boundaries:

Si (3 t) - Si (t)

= Si (3 t) - Si (t)

\int_{0}^{\infty} x^{5} d x

\int_{0}^{1} (2 x - 1)^{10} d x

\int_{0}^{π} (1 + cos (x)) d x

\int_{0}^{1} x^{1} ln (x) d x

\int_{x^{3}}^{x} e^{\frac{2 y}{x}} d y

What is the integral from t to 3t of (sin(x))/x ?
The integral from t to 3t of (sin(x))/x is \Si(3t)-\Si(t)