What is the integral from 0 to t of e^x ?

The integral from 0 to t of e^x is e^t-1

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integral from 0 to t of e^x

\int_{0}^{t} e^{x} d x

e^{t} - 1

Solution steps

\int_{0}^{t} e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= [e^{x}]_{0}^{t}

Compute the boundaries:

e^{t} - 1

= e^{t} - 1

\int_{0}^{\frac{π}{2}} cos (x^{2}) d x

\int_{3}^{4} ln (x) d x

\int_{0}^{1} x x + 1 d x

\int_{0}^{x^{2}} 1 + t^{2} d t

\int_{- 1}^{1} 2 x + 3 d x

What is the integral from 0 to t of e^x ?
The integral from 0 to t of e^x is e^t-1