What is the integral from-1 to 1 of \sqrt[3]{x^5} ?

The integral from-1 to 1 of \sqrt[3]{x^5} is 0

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integral from-1 to 1 of \sqrt[3]{x^5}

\int_{- 1}^{1} 3 x^{5} d x

0

Solution steps

\int_{- 1}^{1} 3 x^{5} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

3 x^{5} :

Odd

= 0

\int_{0}^{\frac{π}{2}} x sin^{2} (x) d x

\int_{- 1}^{1} 3 x^{3} - x^{2} + x - 1 d x

\int_{1}^{2} \frac{x}{1 + x ^{2}} d x

\int_{0}^{x} 10 x^{2} y d y

\int_{0}^{6} ∣ x - 3 ∣ d x

What is the integral from-1 to 1 of \sqrt[3]{x^5} ?
The integral from-1 to 1 of \sqrt[3]{x^5} is 0