What is the integral from 0 to 2 of x^3-6x^2+8x ?

The integral from 0 to 2 of x^3-6x^2+8x is 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of x^3-6x^2+8x

\int_{0}^{2} x^{3} - 6 x^{2} + 8 x d x

4

Solution steps

\int_{0}^{2} x^{3} - 6 x^{2} + 8 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x^{3} d x - \int_{0}^{2} 6 x^{2} d x + \int_{0}^{2} 8 x d x

\int_{0}^{2} x^{3} d x = 4

\int_{0}^{2} 6 x^{2} d x = 16

\int_{0}^{2} 8 x d x = 16

= 4 - 16 + 16

Simplify

= 4

\int_{0}^{\infty} sin (x^{2}) d x

\int_{0}^{1} x^{4} (2 + 2 x^{5})^{3} d x

\int_{0}^{1} x^{2} (1 - x)^{3} d x

\int_{3}^{0} ∣ 2 x - 3 ∣ d x

\int_{1}^{3} 6 x^{2} d x

What is the integral from 0 to 2 of x^3-6x^2+8x ?
The integral from 0 to 2 of x^3-6x^2+8x is 4