What is the integral from 0 to pi/6 of sin(x) ?

The integral from 0 to pi/6 of sin(x) is -(sqrt(3))/2+1

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integral from 0 to pi/6 of sin(x)

\int_{0}^{\frac{π}{6}} sin (x) d x

- \frac{3}{2} + 1

Decimal

0.13397 \dots

Solution steps

\int_{0}^{\frac{π}{6}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{\frac{π}{6}}

Compute the boundaries:

- \frac{3}{2} + 1

= - \frac{3}{2} + 1

\int_{0}^{x} t^{2} d t

\int_{0}^{2} \frac{x}{x ^{2} + 5} d x

\int_{0}^{2} t^{3} 9 t^{4} + 1 d t

\int_{\frac{π}{2}}^{π} cos (x) + 2 d x

\int_{0}^{\frac{π}{6}} (sec (x) tan (x)) d x

What is the integral from 0 to pi/6 of sin(x) ?
The integral from 0 to pi/6 of sin(x) is -(sqrt(3))/2+1