What is the integral from-1 to 1 of 3x^2 ?

The integral from-1 to 1 of 3x^2 is 2

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integral from-1 to 1 of 3x^2

\int_{- 1}^{1} 3 x^{2} d x

2

Solution steps

\int_{- 1}^{1} 3 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{- 1}^{1} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 1}^{1}

= 3 [\frac{x ^{3}}{3}]_{- 1}^{1}

Compute the boundaries:

\frac{2}{3}

= 3 \cdot \frac{2}{3}

Simplify

= 2

\int_{0}^{π} sin (t) cos (n t) d t

\int_{0}^{1} x^{2} (2 + 2 x^{3})^{3} d x

\int_{- 3}^{2} - x^{2} - x + 6 d x

\int_{- 3}^{3} - x^{2} + 9 d x

\int_{a}^{b} \frac{1}{( x - a ) ^{n}} d x

What is the integral from-1 to 1 of 3x^2 ?
The integral from-1 to 1 of 3x^2 is 2