What is the integral from-3 to 0 of (-x^2-3x) ?

The integral from-3 to 0 of (-x^2-3x) is 9/2

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integral from-3 to 0 of (-x^2-3x)

\int_{- 3}^{0} (- x^{2} - 3 x) d x

\frac{9}{2}

Decimal Notation

4.5

Solution steps

\int_{- 3}^{0} - x^{2} - 3 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 3}^{0} x^{2} d x - \int_{- 3}^{0} 3 x d x

\int_{- 3}^{0} x^{2} d x = 9

\int_{- 3}^{0} 3 x d x = - \frac{27}{2}

= - 9 - (- \frac{27}{2})

Simplify

- 9 - (- \frac{27}{2}) : \frac{9}{2}

= \frac{9}{2}

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What is the integral from-3 to 0 of (-x^2-3x) ?
The integral from-3 to 0 of (-x^2-3x) is 9/2