What is the integral from-1 to 1 of x/(1+x^2) ?

The integral from-1 to 1 of x/(1+x^2) is 0

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integral from-1 to 1 of x/(1+x^2)

\int_{- 1}^{1} \frac{x}{1 + x ^{2}} d x

0

Solution steps

\int_{- 1}^{1} \frac{x}{1 + x ^{2}} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

\frac{x}{1 + x ^{2}} :

Odd

= 0

\int_{- 2}^{2} ∣ x - 1 ∣ d x

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\int_{0}^{2} sin (\frac{nπ x}{2}) d x

\int_{- \frac{π}{2}}^{\frac{π}{2}} x cos (2 x) d x

\int_{9}^{0} ∣ 2 x - 9 ∣ d x

What is the integral from-1 to 1 of x/(1+x^2) ?
The integral from-1 to 1 of x/(1+x^2) is 0