What is the integral from 0 to (3pi)/2 of sin(x) ?

The integral from 0 to (3pi)/2 of sin(x) is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to (3pi)/2 of sin(x)

\int_{0}^{\frac{3 π}{2}} sin (x) d x

1

Solution steps

\int_{0}^{\frac{3 π}{2}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{\frac{3 π}{2}}

Compute the boundaries:

1

= 1

\int_{0}^{2} 12 x^{2} + 4 x - 3 d x

\int_{0}^{4} (x - 3) (x - 5) d x

\int_{1}^{4} \frac{1}{x + 1} d x

\int_{1}^{4} 2 x + 1 d x

\int_{- 1}^{1} x^{2} 1 - x^{2} d x

What is the integral from 0 to (3pi)/2 of sin(x) ?
The integral from 0 to (3pi)/2 of sin(x) is 1