What is the integral from 0 to (3pi)/4 of sec^2(x) ?

The integral from 0 to (3pi)/4 of sec^2(x) is diverges

Popular >

integral from 0 to (3pi)/4 of sec^2(x)

\int_{0}^{\frac{3 π}{4}} sec^{2} (x) d x

diverges

Solution steps

\int_{0}^{\frac{3 π}{4}} sec^{2} (x) d x

Take the denominator(s) of

sec^{2} (x)

and compare to zero:

x = \frac{π}{2}

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{0}^{\frac{π}{2}} sec^{2} (x) d x + \int_{\frac{π}{2}}^{\frac{3 π}{4}} sec^{2} (x) d x

\int_{0}^{\frac{π}{2}} sec^{2} (x) d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\int_{0}^{\infty} x sin (x) d x

\int_{- 1}^{4} (x^{2} - 3 x - 4) d x

\int_{0}^{\frac{1}{2}} x cos (π x) d x

\int_{0}^{4} (1 - e^{- x}) d x

\int_{0}^{1} x ln (x) d x

What is the integral from 0 to (3pi)/4 of sec^2(x) ?
The integral from 0 to (3pi)/4 of sec^2(x) is diverges