What is the integral from 1 to x of x^2 ?

The integral from 1 to x of x^2 is (x^3-1)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to x of x^2

\int_{1}^{x} x^{2} d x

\frac{x ^{3} - 1}{3}

Solution steps

\int_{1}^{x} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{1}^{x}

= [\frac{x ^{3}}{3}]_{1}^{x}

Compute the boundaries:

\frac{x ^{3}}{3} - \frac{1}{3}

= \frac{x ^{3}}{3} - \frac{1}{3}

Simplify

= \frac{x ^{3} - 1}{3}

\int_{\frac{π}{4}}^{\frac{π}{2}} \frac{sin ( x )}{x} d x

\int_{- 4}^{4} - \frac{1}{5} x^{3} + 5 x d x

\int_{1}^{2} e^{2 x} d x

\int_{1}^{5} 1 + \frac{1}{u} + \frac{1}{u ^{2}} d u

\int_{- 1}^{3} \frac{e ^{2 x}}{e ^{x} + 1} d x

What is the integral from 1 to x of x^2 ?
The integral from 1 to x of x^2 is (x^3-1)/3