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Popular >

integral from-2 to 2 of |x+1|

Solution

\int_{- 2}^{2} ∣ x + 1 ∣ d x

Solution

5

Solution steps

\int_{- 2}^{2} ∣ x + 1 ∣ d x

Eliminate Absolutes

= \int_{- 2}^{- 1} - x - 1 d x + \int_{- 1}^{2} x + 1 d x

\int_{- 2}^{- 1} - x - 1 d x = \frac{1}{2}

\int_{- 1}^{2} x + 1 d x = \frac{9}{2}

= \frac{1}{2} + \frac{9}{2}

Simplify

\frac{1}{2} + \frac{9}{2} : 5

= 5

Popular Examples

integral from 1 to 0 of |2x-1|

\int_{1}^{0} ∣ 2 x - 1 ∣ d x

integral from 0 to 2 of 3x^2sqrt(x^3+1)

\int_{0}^{2} 3 x^{2} x^{3} + 1 d x

integral from-1 to 1 of 1/(x^2-4)

\int_{- 1}^{1} \frac{1}{x ^{2} - 4} d x

integral from 1 to e^2 of ((ln(x))^2)/x

\int_{1}^{e^{2}} \frac{( ln ( x ) ) ^{2}}{x} d x

integral from 0 to 1 of sin(pi)x

\int_{0}^{1} sin (π) x d x

Frequently Asked Questions (FAQ)

What is the integral from-2 to 2 of |x+1| ?
The integral from-2 to 2 of |x+1| is 5