What is the integral from 0 to 4 of xsqrt(x^2+3) ?

The integral from 0 to 4 of xsqrt(x^2+3) is (19sqrt(19))/3-sqrt(3)

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integral from 0 to 4 of xsqrt(x^2+3)

\int_{0}^{4} x x^{2} + 3 d x

\frac{19 19}{3} - 3

Decimal Notation

25.87430 \dots

Solution steps

\int_{0}^{4} x x^{2} + 3 d x

Apply u-substitution

: \int_{3}^{19} u^{2} d u

= \int_{3}^{19} u^{2} d u

Apply the Power Rule

: [\frac{u ^{3}}{3}]_{3}^{19}

= [\frac{u ^{3}}{3}]_{3}^{19}

Compute the boundaries:

\frac{19 19}{3} - 3

= \frac{19 19}{3} - 3

\int_{0}^{1} (x^{2} + 4) e^{3 x} d x

\int_{0}^{4} x x^{2} + 6 d x

\int_{0}^{1} x^{2} (2 + 2 x^{3})^{5} d x

\int_{\frac{3 π}{2}}^{2 π} x sin (x) d x

\int_{0}^{3} x^{2} e^{x^{3}} d x

What is the integral from 0 to 4 of xsqrt(x^2+3) ?
The integral from 0 to 4 of xsqrt(x^2+3) is (19sqrt(19))/3-sqrt(3)