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Popular >

integral from 0 to 4 of (x^2-2x)

Solution

\int_{0}^{4} (x^{2} - 2 x) d x

Solution

\frac{16}{3}

+1

Decimal Notation

5.33333 \dots

Solution steps

\int_{0}^{4} x^{2} - 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} x^{2} d x - \int_{0}^{4} 2 x d x

\int_{0}^{4} x^{2} d x = \frac{64}{3}

\int_{0}^{4} 2 x d x = 16

= \frac{64}{3} - 16

Simplify

\frac{64}{3} - 16 : \frac{16}{3}

= \frac{16}{3}

Popular Examples

integral from 0 to 3 of e^{3x}

\int_{0}^{3} e^{3 x} d x

integral from 1 to 4 of xsqrt(3-x)

\int_{1}^{4} x 3 - x d x

integral from x to 0 of sqrt(t^2+4)

\int_{x}^{0} t^{2} + 4 d t

integral from pi/6 to pi/3 of csc^3(x)

\int_{\frac{π}{6}}^{\frac{π}{3}} csc^{3} (x) d x

integral from 0 to 4 of sqrt(4x-x^2)

\int_{0}^{4} 4 x - x^{2} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of (x^2-2x) ?
The integral from 0 to 4 of (x^2-2x) is 16/3