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Popular >

integral from 0 to 1 of (1+x^2)

Solution

\int_{0}^{1} (1 + x^{2}) d x

Solution

\frac{4}{3}

+1

Decimal Notation

1.33333 \dots

Solution steps

\int_{0}^{1} 1 + x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 1 d x + \int_{0}^{1} x^{2} d x

\int_{0}^{1} 1 d x = 1

\int_{0}^{1} x^{2} d x = \frac{1}{3}

= 1 + \frac{1}{3}

Simplify

1 + \frac{1}{3} : \frac{4}{3}

= \frac{4}{3}

Popular Examples

integral from 1 to 2 of e^{-2x}

\int_{1}^{2} e^{- 2 x} d x

integral from 1 to 3 of 5x

\int_{1}^{3} 5 x d x

integral from 0 to infinity of te^{-pt}

\int_{0}^{\infty} t e^{- pt} d t

integral from 0 to 4 of (x-3)(x-1)

\int_{0}^{4} (x - 3) (x - 1) d x

integral from 0 to 1 of ze^{-z^2}

\int_{0}^{1} z e^{- z^{2}} d z

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (1+x^2) ?
The integral from 0 to 1 of (1+x^2) is 4/3