What is the integral from 0 to 1 of 1/y ?

The integral from 0 to 1 of 1/y is diverges

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integral from 0 to 1 of 1/y

\int_{0}^{1} \frac{1}{y} d y

diverges

Solution steps

\int_{0}^{1} \frac{1}{y} d y

Use the common integral:

\int \frac{1}{y} d y = ln (∣ y ∣)

= [ln ∣ y ∣]_{0}^{1}

Compute the boundaries:

diverges

= diverges

\int_{- 1}^{5} ∣ x ∣ d x

\int_{0}^{1} \frac{2}{5} (2 x + 3 y) d y

\int_{- 2}^{3} x^{2} d x

\int_{0}^{2} t e^{- s t} d t

\int_{0}^{3} \frac{2}{x + 1} d x

What is the integral from 0 to 1 of 1/y ?
The integral from 0 to 1 of 1/y is diverges