What is the integral from 0 to x^2 of 3sin(x) ?

The integral from 0 to x^2 of 3sin(x) is 3(-cos(x^2)+1)

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integral from 0 to x^2 of 3sin(x)

\int_{0}^{x^{2}} 3 sin (x) d x

3 (- cos (x^{2}) + 1)

Solution steps

\int_{0}^{x^{2}} 3 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{x^{2}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 3 [- cos (x)]_{0}^{x^{2}}

Compute the boundaries:

- cos (x^{2}) + 1

= 3 (- cos (x^{2}) + 1)

\int_{0}^{\frac{π}{2}} 2 sin (x) d x

\int_{- \infty}^{- 1} e^{x} d x

\int_{y}^{2} t^{3} sin (t) d t

\int_{0}^{1} (x - x^{2})^{2} d x

\int_{1}^{4} 2 x d x

What is the integral from 0 to x^2 of 3sin(x) ?
The integral from 0 to x^2 of 3sin(x) is 3(-cos(x^2)+1)