What is the integral from-1 to 0 of sqrt(x+1) ?

The integral from-1 to 0 of sqrt(x+1) is 2/3

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integral from-1 to 0 of sqrt(x+1)

\int_{- 1}^{0} x + 1 d x

\frac{2}{3}

Decimal Notation

0.66666 \dots

Solution steps

\int_{- 1}^{0} x + 1 d x

Apply u-substitution

: \int_{0}^{1} u d u

= \int_{0}^{1} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{1}

= [\frac{2}{3} u^{\frac{3}{2}}]_{0}^{1}

Compute the boundaries:

\frac{2}{3}

= \frac{2}{3}

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What is the integral from-1 to 0 of sqrt(x+1) ?
The integral from-1 to 0 of sqrt(x+1) is 2/3