What is the integral from 0 to t of sin(t) ?

The integral from 0 to t of sin(t) is -cos(t)+1

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integral from 0 to t of sin(t)

\int_{0}^{t} sin (t) d t

- cos (t) + 1

Solution steps

\int_{0}^{t} sin (t) d t

Use the common integral:

\int sin (t) d t = - cos (t)

= [- cos (t)]_{0}^{t}

Compute the boundaries:

- cos (t) + 1

= - cos (t) + 1

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\int_{- 2}^{0} 2 d x

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What is the integral from 0 to t of sin(t) ?
The integral from 0 to t of sin(t) is -cos(t)+1