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Popular >

integral from 0 to 1 of-x+1

Solution

\int_{0}^{1} - x + 1 d x

Solution

\frac{1}{2}

+1

Decimal Notation

0.5

Solution steps

\int_{0}^{1} - x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{1} x d x + \int_{0}^{1} 1 d x

\int_{0}^{1} x d x = \frac{1}{2}

\int_{0}^{1} 1 d x = 1

= - \frac{1}{2} + 1

Simplify

- \frac{1}{2} + 1 : \frac{1}{2}

= \frac{1}{2}

Popular Examples

integral from 0 to 1 of 4xf(x^2+1)

\int_{0}^{1} 4 x f (x^{2} + 1) d x

integral from 0 to pi/2 of (sin(x))/x

\int_{0}^{\frac{π}{2}} \frac{sin ( x )}{x} d x

integral from 0 to 5/6 of 1/(36x^2+25)

\int_{0}^{\frac{5}{6}} \frac{1}{36 x ^{2} + 25} d x

integral from 0 to pi/2 of cos^3(θ)

\int_{0}^{\frac{π}{2}} cos^{3} (θ) d θ

integral from 1 to 3 of x/(4-x^2)

\int_{1}^{3} \frac{x}{4 - x ^{2}} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of-x+1 ?
The integral from 0 to 1 of-x+1 is 1/2