What is the integral from 0 to 2 of (x^3-4x+3) ?

The integral from 0 to 2 of (x^3-4x+3) is 2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of (x^3-4x+3)

\int_{0}^{2} (x^{3} - 4 x + 3) d x

2

Solution steps

\int_{0}^{2} x^{3} - 4 x + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x^{3} d x - \int_{0}^{2} 4 x d x + \int_{0}^{2} 3 d x

\int_{0}^{2} x^{3} d x = 4

\int_{0}^{2} 4 x d x = 8

\int_{0}^{2} 3 d x = 6

= 4 - 8 + 6

Simplify

= 2

\int_{0}^{1} x (x^{2} + 3)^{n} d x

\int_{- 2}^{0} \frac{1}{x ^{3}} d x

\int_{1}^{3} (2 x + \frac{2}{x}) d x

\int_{- 4}^{2} (x^{2} + 2 x - 8) d x

\int_{- \frac{π}{6}}^{\frac{π}{6}} 7 sec^{2} (x) d x

What is the integral from 0 to 2 of (x^3-4x+3) ?
The integral from 0 to 2 of (x^3-4x+3) is 2