What is the integral from pi to 2pi of cos(θ) ?

The integral from pi to 2pi of cos(θ) is 0

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integral from pi to 2pi of cos(θ)

\int_{π}^{2 π} cos (θ) d θ

0

Solution steps

\int_{π}^{2 π} cos (θ) d θ

Use the common integral:

\int cos (θ) d θ = sin (θ)

= [sin (θ)]_{π}^{2 π}

Compute the boundaries:

0

= 0

\int_{- 2}^{2} 8 - x^{2} d x

\int_{- 1}^{1} (z + 1)^{5} d z

\int_{1}^{2} \frac{1}{x ^{2} - 6 x + 9} d x

\int_{0}^{\frac{π}{3}} x tan^{2} (x) d x

\int_{0}^{x} cos^{2} (t) d t

What is the integral from pi to 2pi of cos(θ) ?
The integral from pi to 2pi of cos(θ) is 0