What is the integral from 0 to (3pi)/4 of sin(x) ?

The integral from 0 to (3pi)/4 of sin(x) is 1/(sqrt(2))+1

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integral from 0 to (3pi)/4 of sin(x)

\int_{0}^{\frac{3 π}{4}} sin (x) d x

\frac{1}{2} + 1

Decimal Notation

1.70710 \dots

Solution steps

\int_{0}^{\frac{3 π}{4}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{\frac{3 π}{4}}

Compute the boundaries:

\frac{1}{2} + 1

= \frac{1}{2} + 1

\int_{- 8}^{\infty} - e^{- x} d x

\int_{0}^{1} 3 x^{4} d x

\int_{- 1}^{0} \frac{1}{1 + cos ( x )} d x

\int_{0}^{π} sin (x) \cdot cos (n x) d x

\int_{- 1}^{4} x^{2} - 3 x - 4 d x

What is the integral from 0 to (3pi)/4 of sin(x) ?
The integral from 0 to (3pi)/4 of sin(x) is 1/(sqrt(2))+1