What is the integral from 0 to 1 of-x ?

The integral from 0 to 1 of-x is -1/2

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integral from 0 to 1 of-x

\int_{0}^{1} - x d x

- \frac{1}{2}

Decimal Notation

- 0.5

Solution steps

\int_{0}^{1} - x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{0}^{1} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{1}

= - [\frac{x ^{2}}{2}]_{0}^{1}

Compute the boundaries:

\frac{1}{2}

= - \frac{1}{2}

\int_{0}^{2} 9 x^{2} x^{3} + 1 d x

\int_{- 2}^{2} \frac{1}{x + 1} d x

\int_{0}^{1} 2 t 1 + 4 t^{2} d t

\int_{- 1}^{1} \frac{x}{x ^{2} + x + 1} d x

\int_{2}^{5} \frac{1}{( x - 1 ) ( x + 2 )} d x