What is the derivative of (-6x/(sqrt(2x-1))) ?

The derivative of (-6x/(sqrt(2x-1))) is -(6(x-1))/((2x-1)sqrt(2x-1))

What is the first derivative of (-6x/(sqrt(2x-1))) ?

The first derivative of (-6x/(sqrt(2x-1))) is -(6(x-1))/((2x-1)sqrt(2x-1))

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\frac{d}{d x} (\frac{- 6 x}{2 x - 1})

- \frac{6 ( x - 1 )}{( 2 x - 1 ) 2 x - 1}

Solution steps

\frac{d}{d x} (\frac{- 6 x}{2 x - 1})

Simplify

\frac{- 6 x}{2 x - 1} : - \frac{6 x}{2 x - 1}

= \frac{d}{d x} (- \frac{6 x}{2 x - 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 6 \frac{d}{d x} (\frac{x}{2 x - 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= - 6 \cdot \frac{\frac{d x}{d x} 2 x - 1 - \frac{d}{d x} ( 2 x - 1 ) x}{( 2 x - 1 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (2 x - 1) = \frac{1}{2 x - 1}

= - 6 \cdot \frac{1 \cdot 2 x - 1 - \frac{1}{2 x - 1} x}{( 2 x - 1 ) ^{2}}

Simplify

- 6 \cdot \frac{1 \cdot 2 x - 1 - \frac{1}{2 x - 1} x}{( 2 x - 1 ) ^{2}} : - \frac{6 ( x - 1 )}{( 2 x - 1 ) 2 x - 1}

= - \frac{6 ( x - 1 )}{( 2 x - 1 ) 2 x - 1}

\frac{4 x ^{5} + 7}{x ^{3}}

\frac{d}{d x} (ln (\frac{x ^{2} + 1}{x + 4}))

y^{^{''}} + 3 y^{^{'}} + 2 y = 0, y (0) = 2, y (1) = 3

x \to 7 + lim (ln (x - 7))

\int e^{7 x + 9} d x

What is the derivative of (-6x/(sqrt(2x-1))) ?
The derivative of (-6x/(sqrt(2x-1))) is -(6(x-1))/((2x-1)sqrt(2x-1))
What is the first derivative of (-6x/(sqrt(2x-1))) ?
The first derivative of (-6x/(sqrt(2x-1))) is -(6(x-1))/((2x-1)sqrt(2x-1))