What is the integral from 0 to 1 of 1/(x^{sqrt(3))} ?

The integral from 0 to 1 of 1/(x^{sqrt(3))} is (-sqrt(3)-1+sqrt(3)*0^{-sqrt(3)+1}+0^{-sqrt(3)+1})/2

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integral from 0 to 1 of 1/(x^{sqrt(3))}

\int_{0}^{1} \frac{1}{x ^{3}} d x

\frac{- 3 - 1 + 3 \cdot 0 ^{- 3 + 1} + 0 ^{- 3 + 1}}{2}

Solution steps

\int_{0}^{1} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{3 + 1}{2} x^{- 3 + 1}]_{0}^{1}

= [- \frac{3 + 1}{2} x^{- 3 + 1}]_{0}^{1}

Compute the boundaries:

\frac{- 3 - 1 + 3 \cdot 0 ^{- 3 + 1} + 0 ^{- 3 + 1}}{2}

= \frac{- 3 - 1 + 3 \cdot 0 ^{- 3 + 1} + 0 ^{- 3 + 1}}{2}

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\int_{0}^{2} (x - 1) d x

\int_{1}^{2} (4 x^{3} - 3 x^{2} + 2) d x

\int_{2}^{3} \frac{x + 1}{x} d x

What is the integral from 0 to 1 of 1/(x^{sqrt(3))} ?
The integral from 0 to 1 of 1/(x^{sqrt(3))} is (-sqrt(3)-1+sqrt(3)*0^{-sqrt(3)+1}+0^{-sqrt(3)+1})/2