What is the integral from 0 to pi of (sin(x)-8) ?

The integral from 0 to pi of (sin(x)-8) is 2-8pi

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integral from 0 to pi of (sin(x)-8)

\int_{0}^{π} (sin (x) - 8) d x

2 - 8 π

Decimal Notation

- 23.13274 \dots

Solution steps

\int_{0}^{π} sin (x) - 8 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{π} sin (x) d x - \int_{0}^{π} 8 d x

\int_{0}^{π} sin (x) d x = 2

\int_{0}^{π} 8 d x = 8 π

= 2 - 8 π

\int_{0}^{\frac{π}{2}} 9 cos^{2} (θ) d θ

\int_{0}^{4} (8 - t) t d t

\int_{- \infty}^{0} x^{3} d x

\int_{0}^{5} \frac{x}{x ^{2} + 11} d x

\int_{0}^{3} \frac{x}{9 - x} d x

What is the integral from 0 to pi of (sin(x)-8) ?
The integral from 0 to pi of (sin(x)-8) is 2-8pi