What is the derivative of f(x)=sqrt(x+8) ?

The derivative of f(x)=sqrt(x+8) is 1/(2sqrt(x+8))

What is the first derivative of f(x)=sqrt(x+8) ?

The first derivative of f(x)=sqrt(x+8) is 1/(2sqrt(x+8))

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derivative of

f (x) = x + 8

\frac{1}{2 x + 8}

Solution steps

\frac{d}{d x} (x + 8)

Apply the chain rule:

\frac{1}{2 x + 8} \frac{d}{d x} (x + 8)

= \frac{1}{2 x + 8} \frac{d}{d x} (x + 8)

\frac{d}{d x} (x + 8) = 1

= \frac{1}{2 x + 8} \cdot 1

Simplify

= \frac{1}{2 x + 8}

\int t ln (1 + t) d t

\int_{- 8}^{0} (\frac{y}{8} + y + 9) d y

x \to \infty lim (x + 9)

\int \frac{1}{x ^{2} + 3 x + 3} d x

x \to 0 lim (- arcsin (x))

What is the derivative of f(x)=sqrt(x+8) ?
The derivative of f(x)=sqrt(x+8) is 1/(2sqrt(x+8))
What is the first derivative of f(x)=sqrt(x+8) ?
The first derivative of f(x)=sqrt(x+8) is 1/(2sqrt(x+8))