What is the integral from-1 to 4 of 2/(3x^2) ?

The integral from-1 to 4 of 2/(3x^2) is diverges

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integral from-1 to 4 of 2/(3x^2)

\int_{- 1}^{4} \frac{2}{3 x ^{2}} d x

diverges

Solution steps

\int_{- 1}^{4} \frac{2}{3 x ^{2}} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 1}^{0} \frac{2}{3 x ^{2}} d x + \int_{0}^{4} \frac{2}{3 x ^{2}} d x

\int_{- 1}^{0} \frac{2}{3 x ^{2}} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\int_{1}^{- 1} (12 r + 11)^{2} d r

\int_{- 1}^{0} \frac{1}{x ^{2} - 4} d x

\int_{0}^{2} - t^{2} + 3 t - 2 d t

\int_{0}^{1} \frac{1}{x ^{2} + 1} d x

\int_{0}^{1} ln (1 + x) d x

What is the integral from-1 to 4 of 2/(3x^2) ?
The integral from-1 to 4 of 2/(3x^2) is diverges