What is the integral from 0 to 1 of 1/((1+x^2)) ?

The integral from 0 to 1 of 1/((1+x^2)) is pi/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of 1/((1+x^2))

\int_{0}^{1} \frac{1}{( 1 + x ^{2} )} d x

\frac{π}{4}

Decimal Notation

0.78539 \dots

Solution steps

\int_{0}^{1} \frac{1}{1 + x ^{2}} d x

Use the common integral:

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= [arctan (x)]_{0}^{1}

Compute the boundaries:

\frac{π}{4}

= \frac{π}{4}

\int_{0}^{8} \frac{1}{x ^{2} + 64} d x

\int_{0}^{t} e^{- t} d t

\int_{6}^{11} 4 - 10 e^{- 0.2 x} d x

\int_{0}^{1} π x d x

\int_{0}^{9} \frac{x}{x ^{2} + 1} d x

What is the integral from 0 to 1 of 1/((1+x^2)) ?
The integral from 0 to 1 of 1/((1+x^2)) is pi/4