What is the integral from 1 to x of 1/(x^2) ?

The integral from 1 to x of 1/(x^2) is -1/x+1

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integral from 1 to x of 1/(x^2)

\int_{1}^{x} \frac{1}{x ^{2}} d x

- \frac{1}{x} + 1

Solution steps

\int_{1}^{x} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{x}

= [- \frac{1}{x}]_{1}^{x}

Compute the boundaries:

- \frac{1}{x} + 1

= - \frac{1}{x} + 1

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What is the integral from 1 to x of 1/(x^2) ?
The integral from 1 to x of 1/(x^2) is -1/x+1