What is the integral from 0 to y of e^{-y^2} ?

The integral from 0 to y of e^{-y^2} is (sqrt(pi))/2 \erf(y)

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integral from 0 to y of e^{-y^2}

\int_{0}^{y} e^{- y^{2}} d y

\frac{π}{2} erf (y)

Solution steps

\int_{0}^{y} e^{- y^{2}} d y

Use the nonelementary integral:

\int e^{- y^{2}} d y = \frac{π}{2} erf (y)

= [\frac{π}{2} erf (y)]_{0}^{y}

Compute the boundaries:

\frac{π}{2} erf (y)

= \frac{π}{2} erf (y)

\int_{0}^{π} x^{2} sin (3 x) d x

\int_{0}^{2} t d t

\int_{0}^{π} (6 sin (x)) d x

\int_{0}^{1} sin (5 x) d x

\int_{0}^{1} x + \frac{3}{2} y^{2} d y

What is the integral from 0 to y of e^{-y^2} ?
The integral from 0 to y of e^{-y^2} is (sqrt(pi))/2 \erf(y)