What is the integral from 1/2 to 1 of sin(2pi)x ?

The integral from 1/2 to 1 of sin(2pi)x is 0

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integral from 1/2 to 1 of sin(2pi)x

\int_{\frac{1}{2}}^{1} sin (2 π) x d x

0

Solution steps

\int_{\frac{1}{2}}^{1} sin (2 π) x d x

sin (2 π) x = 0

= \int_{\frac{1}{2}}^{1} 0 d x

Integral of a constant:

\int a d x = a x

= [0 \cdot x]_{\frac{1}{2}}^{1}

Simplify

= [0]_{\frac{1}{2}}^{1}

Compute the boundaries:

0

= 0

\int_{- 7}^{\infty} - 2 e^{2 x} d x

\int_{1}^{e^{2}} x ln (x) d x

\int_{0}^{1} 4 cos (\frac{π x}{2}) d x

\int_{0}^{1} (x^{11} + 1 1^{x}) d x

\int_{- 2}^{1} (2 - x - x^{2}) d x

What is the integral from 1/2 to 1 of sin(2pi)x ?
The integral from 1/2 to 1 of sin(2pi)x is 0