en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of |x^2-x|

Solution

\int_{0}^{2} x^{2} - x d x

Solution

1

Solution steps

\int_{0}^{2} x^{2} - x d x

Eliminate Absolutes

= \int_{0}^{1} - x^{2} + x d x + \int_{1}^{2} x^{2} - x d x

\int_{0}^{1} - x^{2} + x d x = \frac{1}{6}

\int_{1}^{2} x^{2} - x d x = \frac{5}{6}

= \frac{1}{6} + \frac{5}{6}

Simplify

\frac{1}{6} + \frac{5}{6} : 1

= 1

Popular Examples

integral from x to x+2 of 1/24 (x+y)

\int_{x}^{x + 2} \frac{1}{24} (x + y) d y

integral from 0 to 1 of (x^2+2)e^{4x}

\int_{0}^{1} (x^{2} + 2) e^{4 x} d x

integral from 0 to pi of 1+cos(x)

\int_{0}^{π} 1 + cos (x) d x

integral from 0 to 0.5 of e^{-x^2}

\int_{0}^{0.5} e^{- x^{2}} d x

integral from 0 to 1 of sqrt(x^2+y^2)

\int_{0}^{1} x^{2} + y^{2} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of |x^2-x| ?
The integral from 0 to 2 of |x^2-x| is 1