What is the integral from 0 to (5pi)/6 of sin(x) ?

The integral from 0 to (5pi)/6 of sin(x) is (sqrt(3))/2+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to (5pi)/6 of sin(x)

\int_{0}^{\frac{5 π}{6}} sin (x) d x

\frac{3}{2} + 1

Decimal Notation

1.86602 \dots

Solution steps

\int_{0}^{\frac{5 π}{6}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{\frac{5 π}{6}}

Compute the boundaries:

\frac{3}{2} + 1

= \frac{3}{2} + 1

\int_{0}^{1} 8 cos (\frac{π x}{2}) d x

\int_{0}^{1} (x^{2} + x - 1) d x

\int_{0}^{2 π} cos (n x) d x

\int_{0}^{3 x} f (t) d t

\int_{2}^{\infty} \frac{1}{1 - x ^{2}} d x

What is the integral from 0 to (5pi)/6 of sin(x) ?
The integral from 0 to (5pi)/6 of sin(x) is (sqrt(3))/2+1