What is the integral from 0 to 5x of f(t) ?

The integral from 0 to 5x of f(t) is (25x^2f)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 5x of f(t)

\int_{0}^{5 x} f (t) d t

\frac{25 x ^{2} f}{2}

Solution steps

\int_{0}^{5 x} f t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= f \cdot \int_{0}^{5 x} t d t

Apply the Power Rule

: [\frac{t ^{2}}{2}]_{0}^{5 x}

= f [\frac{t ^{2}}{2}]_{0}^{5 x}

Compute the boundaries:

\frac{25 x ^{2}}{2}

= f \frac{25 x ^{2}}{2}

Simplify

= \frac{25 x ^{2} f}{2}

\int_{- 4}^{4} x^{2} d x

\int_{- 1}^{6} ∣ x ∣ d x

\int_{0}^{3} 5 x^{2} d x

\int_{0}^{1} (x^{2} - 4 x + 8) d x

\int_{0}^{2} 5 - x^{2} d x

What is the integral from 0 to 5x of f(t) ?
The integral from 0 to 5x of f(t) is (25x^2f)/2