What is the integral from 4 to 6 of (x^2+2x-3) ?

The integral from 4 to 6 of (x^2+2x-3) is 194/3

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integral from 4 to 6 of (x^2+2x-3)

\int_{4}^{6} (x^{2} + 2 x - 3) d x

\frac{194}{3}

Decimal Notation

64.66666 \dots

Solution steps

\int_{4}^{6} x^{2} + 2 x - 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{4}^{6} x^{2} d x + \int_{4}^{6} 2 x d x - \int_{4}^{6} 3 d x

\int_{4}^{6} x^{2} d x = \frac{152}{3}

\int_{4}^{6} 2 x d x = 20

\int_{4}^{6} 3 d x = 6

= \frac{152}{3} + 20 - 6

Simplify

\frac{152}{3} + 20 - 6 : \frac{194}{3}

= \frac{194}{3}

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\int_{- \infty}^{0} \frac{1}{x} d x

\int_{- \frac{π}{2}}^{\frac{π}{2}} 1

\int_{1}^{0} x d x

What is the integral from 4 to 6 of (x^2+2x-3) ?
The integral from 4 to 6 of (x^2+2x-3) is 194/3