What is the integral from-pi/2 to pi/2 of-cos(x) ?

The integral from-pi/2 to pi/2 of-cos(x) is -2

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integral from-pi/2 to pi/2 of-cos(x)

\int_{- \frac{π}{2}}^{\frac{π}{2}} - cos (x) d x

- 2

Solution steps

\int_{- \frac{π}{2}}^{\frac{π}{2}} - cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{- \frac{π}{2}}^{\frac{π}{2}} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= - [sin (x)]_{- \frac{π}{2}}^{\frac{π}{2}}

Compute the boundaries:

2

= - 2

\int_{- 1}^{1} (4 - 9 y) d y

\int_{0}^{1} e^{x} x d x

\int_{0}^{4} 1 + 2 x d x

\int_{0}^{s i n (y)} (1 + cos (y)) d y

\int_{- 2}^{3} \frac{1}{x ^{3}} d x

What is the integral from-pi/2 to pi/2 of-cos(x) ?
The integral from-pi/2 to pi/2 of-cos(x) is -2